but here in my book the answe is 10 m/s
??
they do v0 = 2DX/2-v = 2 X 50 /8 -2.5 = 10
??please I want the help beacuse I fell confused
I wait
Hi ALL
which Equations constant I use here ?
a truck covers a distance of 50 m in 8 s while smoothly sowing down to a final speed of 2.5 m/s . find its original speed
Dx = 50 m
t = 8 s
v = 2.5 m/s
Now I take this equation bit I don't now why I didn't get the correct answer
Dx = (v + v0 ) t/2
=50 = 2.5 + v0 ) 8 /2
=2 X 50 + 92.5 + v0 ) 8 /2
=100 = 20 + 8v0/2
=128v
v = -128