Results 1 to 9 of 9

Math Help - Help a soldja out.

  1. #1
    Junior Member Soldja Soul3ss's Avatar
    Joined
    May 2007
    From
    Algebra hell
    Posts
    32

    Help a soldja out.

    Ahh, need assistance with this stuff, help is like always extremely appreciated. Thanx tons guys.





    Follow Math Help Forum on Facebook and Google+

  2. #2
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by Soldja Soul3ss View Post
    Ahh, need assistance with this stuff, help is like always extremely appreciated. Thanx tons guys.





    Wow, soulja needs a lot o' helpin'

    1) the first is not anything to worry about, just replace a and b with the numbers and work it out using your calculator, that is:

    what is: [(-1)^3 - 3]/[-1 + 3]

    2) a fraction is undefined when the denominator is zero, so the function is undefined for x + 2 = 0

    3) there is a single term in the bottom, just divide it into each

    (8x - 8)/4 = (8/4)x - (8/4)

    or if you want to be elegant, factor a 4 out the top:

    (8x - 8)/4 = 4(2x - 2)/4

    now the answer is blatantly staring you in the face

    4) factorize the top, something should cancel

    when you get those tell me, and if i'm still online i'll help you with the rest
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Junior Member Soldja Soul3ss's Avatar
    Joined
    May 2007
    From
    Algebra hell
    Posts
    32
    Okay i'll try a few out, but algebra is the most intemidating subject for me to even try to comprehend lol.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    Quote Originally Posted by Soldja Soul3ss View Post
    Okay i'll try a few out, but algebra is the most intemidating subject for me to even try to comprehend lol.
    it's like that for everyone, but it becomes easier with practice
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member Soldja Soul3ss's Avatar
    Joined
    May 2007
    From
    Algebra hell
    Posts
    32
    for 1 i got -1

    for 2 im not even sure how to go about

    and for 3 i THINK its E if i had to guess.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Super Member
    Joined
    Oct 2006
    Posts
    679
    Awards
    1

    Re:

    RE:
    1. A
    2. C
    3. C
    4. B
    5. A
    6. See Attachment!
    7.D
    8.A
    9.B
    10. B
    Attached Thumbnails Attached Thumbnails Help a soldja out.-quick-help-.gif  
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member Soldja Soul3ss's Avatar
    Joined
    May 2007
    From
    Algebra hell
    Posts
    32
    woaw #1 was A?!?! i thought for sure i had that right with B
    Follow Math Help Forum on Facebook and Google+

  8. #8
    is up to his old tricks again! Jhevon's Avatar
    Joined
    Feb 2007
    From
    New York, USA
    Posts
    11,663
    Thanks
    3
    For 2 and 3 i pretty much gave you the answers

    Quote Originally Posted by Soldja Soul3ss View Post
    Ahh, need assistance with this stuff, help is like always extremely appreciated. Thanx tons guys.




    1) if a = -1 and b = 3

    then (a^3 - b)/(a + b) = [(-1)^3 - 3]/(-1 + 3) = (-1 - 3)/(2) = -4/2 = -2

    2) as i said, a fraction is undefined where the denominator is zero, so the values of x for which our fraction is undefined comes from the equation:

    x + 2 = 0 ............i would think this is not a hard problem to solve, no matter what your limitations with algebra is, anyway...

    => x + 2 - 2 = 0 - 2 .................subtract 2 from both sides since we want x
    => x = -2

    so -2 is the answer

    3) (8x - 8)/4 = 4(2x - 2)/4 = 2x - 2 ...........the 4's cancel

    4) (x^2 + 3x - 10)/(x + 5) = [(x + 5)(x - 2)]/(x + 5) = x-2 ...the (x + 5)'s cancel
    Follow Math Help Forum on Facebook and Google+

  9. #9
    Super Member
    Joined
    Oct 2006
    Posts
    679
    Awards
    1

    Re:

    Quote Originally Posted by Soldja Soul3ss View Post
    woaw #1 was A?!?! i thought for sure i had that right with B
    RE:

    Defiantly not!! It's A
    Follow Math Help Forum on Facebook and Google+

Search Tags


/mathhelpforum @mathhelpforum