Ahh, need assistance with this stuff, help is like always extremely appreciated. Thanx tons guys.

Results 1 to 9 of 9

- May 6th 2007, 12:39 PM #1

- May 6th 2007, 12:46 PM #2
Wow, soulja needs a lot o' helpin'

1) the first is not anything to worry about, just replace a and b with the numbers and work it out using your calculator, that is:

what is: [(-1)^3 - 3]/[-1 + 3]

2) a fraction is undefined when the denominator is zero, so the function is undefined for x + 2 = 0

3) there is a single term in the bottom, just divide it into each

(8x - 8)/4 = (8/4)x - (8/4)

or if you want to be elegant, factor a 4 out the top:

(8x - 8)/4 = 4(2x - 2)/4

now the answer is blatantly staring you in the face

4) factorize the top, something should cancel

when you get those tell me, and if i'm still online i'll help you with the rest

- May 6th 2007, 12:52 PM #3

- May 6th 2007, 12:53 PM #4

- May 6th 2007, 01:01 PM #5

- May 6th 2007, 01:04 PM #6

- May 6th 2007, 01:07 PM #7

- May 6th 2007, 01:10 PM #8
For 2 and 3 i pretty much gave you the answers

1) if a = -1 and b = 3

then (a^3 - b)/(a + b) = [(-1)^3 - 3]/(-1 + 3) = (-1 - 3)/(2) = -4/2 = -2

2) as i said, a fraction is undefined where the denominator is zero, so the values of x for which our fraction is undefined comes from the equation:

x + 2 = 0 ............i would think this is not a hard problem to solve, no matter what your limitations with algebra is, anyway...

=> x + 2 - 2 = 0 - 2 .................subtract 2 from both sides since we want x

=> x = -2

so -2 is the answer

3) (8x - 8)/4 = 4(2x - 2)/4 = 2x - 2 ...........the 4's cancel

4) (x^2 + 3x - 10)/(x + 5) = [(x + 5)(x - 2)]/(x + 5) = x-2 ...the (x + 5)'s cancel

- May 6th 2007, 01:14 PM #9