# Help a soldja out.

• May 6th 2007, 12:39 PM
Soldja Soul3ss
Help a soldja out.
• May 6th 2007, 12:46 PM
Jhevon
Wow, soulja needs a lot o' helpin'

1) the first is not anything to worry about, just replace a and b with the numbers and work it out using your calculator, that is:

what is: [(-1)^3 - 3]/[-1 + 3]

2) a fraction is undefined when the denominator is zero, so the function is undefined for x + 2 = 0

3) there is a single term in the bottom, just divide it into each

(8x - 8)/4 = (8/4)x - (8/4)

or if you want to be elegant, factor a 4 out the top:

(8x - 8)/4 = 4(2x - 2)/4

now the answer is blatantly staring you in the face

4) factorize the top, something should cancel

when you get those tell me, and if i'm still online i'll help you with the rest
• May 6th 2007, 12:52 PM
Soldja Soul3ss
Okay i'll try a few out, but algebra is the most intemidating subject for me to even try to comprehend lol.
• May 6th 2007, 12:53 PM
Jhevon
Quote:

Originally Posted by Soldja Soul3ss
Okay i'll try a few out, but algebra is the most intemidating subject for me to even try to comprehend lol.

it's like that for everyone, but it becomes easier with practice
• May 6th 2007, 01:01 PM
Soldja Soul3ss
for 1 i got -1

for 2 im not even sure how to go about

and for 3 i THINK its E if i had to guess.
• May 6th 2007, 01:04 PM
qbkr21
Re:
RE:
1. A
2. C
3. C
4. B
5. A
6. See Attachment!
7.D
8.A
9.B
10. B
• May 6th 2007, 01:07 PM
Soldja Soul3ss
woaw #1 was A?!?! i thought for sure i had that right with B :(
• May 6th 2007, 01:10 PM
Jhevon
For 2 and 3 i pretty much gave you the answers

Quote:

Originally Posted by Soldja Soul3ss
Ahh, need assistance with this stuff, help is like always extremely appreciated. Thanx tons guys.

http://img78.imageshack.us/img78/7690/untitled1om5.gif
http://img78.imageshack.us/img78/8061/untitled2bj7.gif

1) if a = -1 and b = 3

then (a^3 - b)/(a + b) = [(-1)^3 - 3]/(-1 + 3) = (-1 - 3)/(2) = -4/2 = -2

2) as i said, a fraction is undefined where the denominator is zero, so the values of x for which our fraction is undefined comes from the equation:

x + 2 = 0 ............i would think this is not a hard problem to solve, no matter what your limitations with algebra is, anyway...

=> x + 2 - 2 = 0 - 2 .................subtract 2 from both sides since we want x
=> x = -2

3) (8x - 8)/4 = 4(2x - 2)/4 = 2x - 2 ...........the 4's cancel

4) (x^2 + 3x - 10)/(x + 5) = [(x + 5)(x - 2)]/(x + 5) = x-2 ...the (x + 5)'s cancel
• May 6th 2007, 01:14 PM
qbkr21
Re:
Quote:

Originally Posted by Soldja Soul3ss
woaw #1 was A?!?! i thought for sure i had that right with B :(

RE:

Defiantly not!! It's A