Four consecutive odd integers are added. If the smallest integer is 2m-1, then how can the sum be represented in terms of m?
well, consecutive integers mean one after another.
So if 2m-1 is the SMALLEST interger. the other numbers need to be larger in value. Since they are ONE after another. The next value up will be +1
since they are odd numbers that means it needs to be +2 each time (+1 will go odd, even, odd, even etc..)
so it will be:
(2m - 1) + (2m + 1) + (2m + 3) + (2m +5)
= 8m + 8
woot! I'm helping! I feel good!
if you don't understand please reply