v=5+24t - 3t^2
v = ds/dt =5+24t - 3t^2
So ds = (5+24t - 3t^2)dt
Find the integration to find the expression for s.
Hi
everyone
please help me with this velocity question:
i got clue how to do it?
here it is:
1. if v=5+24t - 3t^2 , where v m/s is the velocity of the body at a time t seconds.
Determine:
(i) the expression for distance, S, in metres, m.
(ii) how far it moves in the interval t=1 sec to t=5 sec.
thxxxxxxx