Quadratic Equations and kinetics

**mode** · May 1st 2010, 08:48 PM

I think this is the right section to post this but im not 100%

Find the time required for a train to reach 100m if Vo=20m/s (not sure how to do subext) and acceleration is $.5m/s^2$
$<br /> s=20t+(1/2).5t^2<br />$
As far as i know, this is solved using the quadratic formula. How would i go about putting this equation into quadratic form so i can use the quadratic formula?

**pickslides** · May 1st 2010, 08:51 PM

Originally Posted by mode

$<br /> s=20t+(1/2).5t^2<br />$
As far as i know, this is solved using the quadratic formula. How would i go about putting this equation into quadratic form so i can use the quadratic formula?

make $a = \frac{1}{2}\times 0.5 = 0.25$ , $b= 20$ and $c= 0$

**mode** · May 1st 2010, 08:54 PM

would the 2nd number always be a? and would the first nuumber always be b?

**pickslides** · May 1st 2010, 09:02 PM

Originally Posted by mode

would the 2nd number always be a? and would the first nuumber always be b?

No, for $at^2+bt+c = 0 , t= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Do you follow?

**mode** · May 1st 2010, 09:15 PM

yea i do know i was just confused as to where the numbers would go in the quadratic form. But a little thinking has pulled me through but thanks for your help

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