A 100kg man walks up a steep hill that is inclined at $\displaystyle 30\theta$ to the horizontal. After walking $\displaystyle 1.0km$ along this incline, his change in gravitational potential energy will be:

a) $\displaystyle 9.8e5 J$

b) $\displaystyle 8.5e5 J$

c) $\displaystyle 4.9e5 J$ Correct Answer

d) $\displaystyle 6.0e5 J$

Given

$\displaystyle m = 100kg$

$\displaystyle L_{I} = 1km = 1000m$

$\displaystyle 30\theta$ to horizontal

Required

$\displaystyle E_{G}$

Analysis

I'm not exactly sure how to solve this with the given.

Do I have to use the equation $\displaystyle \Delta{E_{G}} = \frac{1}{2}mv^2$?