# [SOLVED] finding angular acceleration

Answer: $0.59rad/s^2$
this is what I did: $\theta = \theta_o +\omega_o t + \frac{1}{2} \alpha t^2 \Leftrightarrow \alpha=\frac{2\theta}{t^2}=\frac{2(3(2\pi)))}{(8s) ^2}$