The equation of a curve is y = 3x^2 - 2x + 1
find the coordinates of the point R on the curve at which the gradient is -14.
do i put the result of dy/dx to equal -14? doing that will not find me 2 points though..
There is only one point at which the gradient is -14 and yes you do solve:Originally Posted by x-disturbed-x
$\displaystyle \frac{dy}{dx}\ =\ -14$
to find the x-coordinate of the point, then substitute that value back
into the original equation to find the corresponding y.
RonL
The x-coordinate of the point at which the derivavtive is -14 isOriginally Posted by x-disturbed-x
-2.
Since the required point is on the curve $\displaystyle y\ =\ 3.x^2\ -\ 2.x\ +\ 1$, and we
already know the x-coordinate, we need only substitute
this into the equation for y will give the y-coordinate.
RonL