btw, this is pie ...
... and this is pi.
Assume that an atom of neon is spherical with a volume V of 4.85 x 10^-24 m^3. If the equation relating radius r and volume V of a sphere is
V = 4/3 pie r^3 (sorry, i don't know how to do the pie symbol on the computer)
determine the atomic radius of a neon atom.
Not sure if I'm right, but I have:
V = 4.85 x 10^-24m^3 = 4/3 pie r^3
0.0485m^3 = 4/3 pie r^3
Is this right? And if so, do I solve it any further? If I'm supposed to, how?
lol, I it was late and I had food on the brain .
So, where it says 3V, would you have
3 x 4.85x10^-24
So radius would equal
r = 1.050068691x10^-8
Don't know if I'm right, or if I'm completely confused?
Where skeeter put 3V you put in the value of V given then evaluate the expression.
According to Data this is about 2 orders of magnitude too large but the calculated answer holds given the volume named