1. ## help answering mole equation?

1. Calculate the mass of 3.88 x 10^14 atoms of N.

I set up the equation as 3.88 x 10^14 N atoms X (1 mole N/6.02 x 10^23) x (14.01 g N/1 mole N)

did I set it up right? and if so I don't know hot to solve. Please help! also I used brackets to show that there are 2 fractions being multiplied...

1. Calculate the mass of 3.88 x 10^14 atoms of N.

I set up the equation as 3.88 x 10^14 N atoms X (1 mole N/6.02 x 10^23) x (14.01 g N/1 mole N)

did I set it up right? and if so I don't know hot to solve. Please help! also I used brackets to show that there are 2 fractions being multiplied...
Lets assume $\displaystyle 6.02 \times 10^{23}$ is Avagadro's number (the number of molecules in a gram molecule of a substance) and that $\displaystyle 14.01$ is the gram molecular weight of Nitrogen.

We have:

$\displaystyle x=\frac{3.88 \times 10^{14} }{6.02 \times 10^{23} }=6.44518 \times 10^{-10}$

of a gram molecule, so the required mass is:

$\displaystyle m=x \times 14.01$ grams

CB