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Math Help - help answering mole equation?

  1. #1
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    help answering mole equation?

    1. Calculate the mass of 3.88 x 10^14 atoms of N.

    I set up the equation as 3.88 x 10^14 N atoms X (1 mole N/6.02 x 10^23) x (14.01 g N/1 mole N)

    did I set it up right? and if so I don't know hot to solve. Please help! also I used brackets to show that there are 2 fractions being multiplied...
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by needhelpplease1 View Post
    1. Calculate the mass of 3.88 x 10^14 atoms of N.

    I set up the equation as 3.88 x 10^14 N atoms X (1 mole N/6.02 x 10^23) x (14.01 g N/1 mole N)

    did I set it up right? and if so I don't know hot to solve. Please help! also I used brackets to show that there are 2 fractions being multiplied...
    Lets assume 6.02 \times 10^{23} is Avagadro's number (the number of molecules in a gram molecule of a substance) and that 14.01 is the gram molecular weight of Nitrogen.

    We have:

    x=\frac{3.88 \times 10^{14} }{6.02 \times 10^{23} }=6.44518 \times 10^{-10}

    of a gram molecule, so the required mass is:

    m=x \times 14.01 grams

    CB
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