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Math Help - [SOLVED] sequencing

  1. #1
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    [SOLVED] sequencing

    I am trying to find the patterns but I don't see any.

    8, 40/3, 152/9, 520/27, 1688/81 I know the denominator is 3^(n-1) *where n starts at 3
    Last edited by Amberosia32; April 12th 2010 at 03:24 AM.
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  2. #2
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    Quote Originally Posted by Amberosia32 View Post
    I am trying to find the patterns but I don't see any.

    8, 40/3, 152/9, 520/27, 1688/81 I know the denominator is 3^(n-1) *where n starts at 3
    a_n = 8 \times 3^{1-n}(3^n - 2^n).
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  3. #3
    Super Member Failure's Avatar
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    Quote Originally Posted by Amberosia32 View Post
    I am trying to find the patterns but I don't see any.

    8, 40/3, 152/9, 520/27, 1688/81 I know the denominator is 3^(n-1) *where n starts at 3
    If you are really, really desperate you can always go to www.wolframalpha.com and just enter your list of numbers. This is what I got:
    8, 40/3, 152/9,520/27,1688/81 - Wolfram|Alpha
    Last edited by Failure; April 12th 2010 at 07:46 AM.
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  4. #4
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    Quote Originally Posted by Failure View Post
    If you are really, really desperate you can always go to www.wolframalpha.com and just enter your list of numbers. This is what I got:
    8, 40/3, 152/9,520/27,1688/81 - Wolfram|Alpha
    That's a very useful tool thank you.
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