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Math Help - Electronics function help.

  1. #1
    Newbie
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    Question Electronics function help.

    Hello,

    Been out of practice so long that all is forgotten.
    I was wondering if someone could help me understand and apply the following expression:

    V = \frac{{1/V_{tn}}}2+\int_{t0}^{t=n-1} \frac{V_{1}...V_{n}/n}2


    It was suggested to me to help smooth out a noisy voltage signal.

    Hugger
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Hugger View Post
    Hello,

    Been out of practice so long that all is forgotten.
    I was wondering if someone could help me understand and apply the following expression:

    V = \frac{{1/V_{tn}}}2+\int_{t0}^{t=n-1} \frac{V_{1}...V_{n}/n}2


    It was suggested to me to help smooth out a noisy voltage signal.

    Hugger
    Please explain you notation, as it is that is meaningless

    CB
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  3. #3
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    Thanks for the response CB.

    I will go back and check to see if I goofed the notation.

    Again, I am trying to come up with an expression that will smooth out samples taken of voltage that is somewhat noisy by averaging a group of samples to get rid of dips and spikes.

    I'll reply when I verify notation.

    Hugger
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  4. #4
    Grand Panjandrum
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    Quote Originally Posted by Hugger View Post
    Thanks for the response CB.

    I will go back and check to see if I goofed the notation.

    Again, I am trying to come up with an expression that will smooth out samples taken of voltage that is somewhat noisy by averaging a group of samples to get rid of dips and spikes.

    I'll reply when I verify notation.

    Hugger
    A moving window smoother would be something like:

    V_n=\frac{1}{m} \sum_{i=n-m+1}^n v_i

    where the v_i are the input samples and the V_n are the smoothed outputs.

    Though this introduces a lag of (m-1)/2 samples. So if m is odd, then:

    V_{n-(m-1)/2}=\frac{1}{m} \sum_{i=n-m+1}^n v_i

    is a moving average smoother with no lag (though there is now latency of (m-1)/2 samples).

    CB
    Last edited by CaptainBlack; March 21st 2010 at 12:29 PM.
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