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Math Help - M1 question- Resolving frictional forces

  1. #1
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    M1 question- Resolving frictional forces

    Hi

    I am having a problem with this question, and was wondering whether I could have a bit of a nudge in the correct direction?

    I cannot do part 'iv'; however, I think that I may have worked out part iv for question iii though Im not sure



    The answers I have so far are:

    A) i)

    Resolve horizontally- 80*cos 25 = 72.5N

    ii)

    Fmax= Coefficient of friction x R:

    Fmax= 0.32*80 = 25.6N

    iii)

    Mass= 80/9.8= 8.16kg

    -> T + 8.16*cos 25 = 80*sin 25

    T= 80*sin 25 - 8.16*cos 25 = 26.14N

    v)

    80/9.8= 8.16kg

    Any help is greately appreciated concerning parts iii and iv
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  2. #2
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    Quote Originally Posted by fishkeeper View Post
    Hi

    I am having a problem with this question, and was wondering whether I could have a bit of a nudge in the correct direction?

    I cannot do part 'iv'; however, I think that I may have worked out part iv for question iii though Im not sure



    The answers I have so far are:

    A) i)

    Resolve horizontally- 80*cos 25 = 72.5N

    ii)

    Fmax= Coefficient of friction x R:

    Fmax= 0.32*80 = 25.6N

    iii)

    Mass= 80/9.8= 8.16kg

    -> T + 8.16*cos 25 = 80*sin 25

    T= 80*sin 25 - 8.16*cos 25 = 26.14N

    v)

    80/9.8= 8.16kg

    Any help is greately appreciated concerning parts iii and iv

    iii) T_{min} = mg\sin{\theta} - f_{s \, max}

    iv) T_{max} = mg\sin{\theta} + f_{s \, max}
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  3. #3
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    thankyou Skeeter

    That helps enourmously!
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