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Thread: M1 question- Resolving frictional forces

  1. #1
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    M1 question- Resolving frictional forces

    Hi

    I am having a problem with this question, and was wondering whether I could have a bit of a nudge in the correct direction?

    I cannot do part 'iv'; however, I think that I may have worked out part iv for question iii though Im not sure



    The answers I have so far are:

    A) i)

    Resolve horizontally- $\displaystyle 80*cos 25 = 72.5N$

    ii)

    Fmax= Coefficient of friction x R:

    $\displaystyle Fmax= 0.32*80 = 25.6N$

    iii)

    Mass= $\displaystyle 80/9.8= 8.16kg$

    -> $\displaystyle T + 8.16*cos 25 = 80*sin 25$

    $\displaystyle T= 80*sin 25 - 8.16*cos 25 = 26.14N$

    v)

    $\displaystyle 80/9.8= 8.16kg$

    Any help is greately appreciated concerning parts iii and iv
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  2. #2
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    Quote Originally Posted by fishkeeper View Post
    Hi

    I am having a problem with this question, and was wondering whether I could have a bit of a nudge in the correct direction?

    I cannot do part 'iv'; however, I think that I may have worked out part iv for question iii though Im not sure



    The answers I have so far are:

    A) i)

    Resolve horizontally- $\displaystyle 80*cos 25 = 72.5N$

    ii)

    Fmax= Coefficient of friction x R:

    $\displaystyle Fmax= 0.32*80 = 25.6N$

    iii)

    Mass= $\displaystyle 80/9.8= 8.16kg$

    -> $\displaystyle T + 8.16*cos 25 = 80*sin 25$

    $\displaystyle T= 80*sin 25 - 8.16*cos 25 = 26.14N$

    v)

    $\displaystyle 80/9.8= 8.16kg$

    Any help is greately appreciated concerning parts iii and iv

    iii) $\displaystyle T_{min} = mg\sin{\theta} - f_{s \, max} $

    iv) $\displaystyle T_{max} = mg\sin{\theta} + f_{s \, max}$
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  3. #3
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    thankyou Skeeter

    That helps enourmously!
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