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Math Help - need homework help

  1. #1
    mimi
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    Question need homework help

    Here's the two questions i'm having problems with:
    1. Complete 1300 cm2 = ____m2.

    2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.

    thank you so much in advance...Mimi
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mimi View Post
    Here's the two questions i'm having problems with:
    1. Complete 1300 cm2 = ____m2.
    ok, we know that 1 cm = 0.01 m right, so we can just stick in 0.01 m where we see cm.

    so 1300 cm^2
    = 1300 (0.01 m)^2
    = 1300 (0.01^2 m^2)
    = 1300(0.0001 m^2)
    = 0.13 m^2



    2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.

    thank you so much in advance...Mimi
    i think you need a diagram here, or at least tell me which length is the hypotenuse, the hypotenuse is the longest side (that's the one opposite the right angle). when you tell me that, we will use pythagoras' theorem to find a
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by mimi View Post
    2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.
    since you can't tell me which side is which, i will give you 2 answers, choose whichever one is closest to the answer in your text or wherever.

    answer 1:

    here i assume a is the hypotenuse, therefore, by pythagoras' theorem:

    a^2 = b^2 + c^2
    => a^2 = 4^2 + 11^2
    => a^2 = 16 + 121
    => a^2 = 137
    => a = sqrt(137)
    => a = 11.705

    answer 2:

    here i assume a is not the hypotenuse. if a is not the hypotenuse, then c is the hypotenuse, since the hypotenuse is the longest side. so by pythagoras' theorem:

    a^2 = c^2 - b^2
    => a^2 = 11^2 - 4^2
    => a^2 = 121 - 16
    => a^2 = 105
    => a = sqrt(105)
    => a = 10.247
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