Here's the two questions i'm having problems with:

1. Complete 1300 cm2 = ____m2.

2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.

thank you so much in advance...Mimi

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- Mar 28th 2007, 08:34 PMmimineed homework help
Here's the two questions i'm having problems with:

1. Complete 1300 cm2 = ____m2.

2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.

thank you so much in advance...Mimi - Mar 28th 2007, 08:45 PMJhevon
ok, we know that 1 cm = 0.01 m right, so we can just stick in 0.01 m where we see cm.

so 1300 cm^2

= 1300 (0.01 m)^2

= 1300 (0.01^2 m^2)

= 1300(0.0001 m^2)

= 0.13 m^2

Quote:

2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.

thank you so much in advance...Mimi

- Mar 28th 2007, 09:13 PMJhevon
since you can't tell me which side is which, i will give you 2 answers, choose whichever one is closest to the answer in your text or wherever.

**answer 1:**

here i assume a is the hypotenuse, therefore, by pythagoras' theorem:

a^2 = b^2 + c^2

=> a^2 = 4^2 + 11^2

=> a^2 = 16 + 121

=> a^2 = 137

=> a = sqrt(137)

=> a = 11.705

**answer 2:**

here i assume a is not the hypotenuse. if a is not the hypotenuse, then c is the hypotenuse, since the hypotenuse is the longest side. so by pythagoras' theorem:

a^2 = c^2 - b^2

=> a^2 = 11^2 - 4^2

=> a^2 = 121 - 16

=> a^2 = 105

=> a = sqrt(105)

=> a = 10.247