Here's the two questions i'm having problems with:
1. Complete 1300 cm2 = ____m2.
2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.
thank you so much in advance...Mimi
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Here's the two questions i'm having problems with:
1. Complete 1300 cm2 = ____m2.
2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.
thank you so much in advance...Mimi
ok, we know that 1 cm = 0.01 m right, so we can just stick in 0.01 m where we see cm.Quote:
Originally Posted by mimi
so 1300 cm^2
= 1300 (0.01 m)^2
= 1300 (0.01^2 m^2)
= 1300(0.0001 m^2)
= 0.13 m^2
i think you need a diagram here, or at least tell me which length is the hypotenuse, the hypotenuse is the longest side (that's the one opposite the right angle). when you tell me that, we will use pythagoras' theorem to find aQuote:
2. given a right triangle with b=4 and c =11, find a approximated to three decimal places.
thank you so much in advance...Mimi
since you can't tell me which side is which, i will give you 2 answers, choose whichever one is closest to the answer in your text or wherever.Quote:
Originally Posted by mimi
answer 1:
here i assume a is the hypotenuse, therefore, by pythagoras' theorem:
a^2 = b^2 + c^2
=> a^2 = 4^2 + 11^2
=> a^2 = 16 + 121
=> a^2 = 137
=> a = sqrt(137)
=> a = 11.705
answer 2:
here i assume a is not the hypotenuse. if a is not the hypotenuse, then c is the hypotenuse, since the hypotenuse is the longest side. so by pythagoras' theorem:
a^2 = c^2 - b^2
=> a^2 = 11^2 - 4^2
=> a^2 = 121 - 16
=> a^2 = 105
=> a = sqrt(105)
=> a = 10.247