An avalanche sliding down a mountain has a constant acceleration of 3.0m/s^2 [W]. It takes 6.0s to cover a displacement off 78m[W].
a) Calculate its initial velocity.
Acceleration = 3.0m/s^2
Time = 6.0s
Displacement = 78m [W]
d = v1(t) + 1/2a(t)^2
(2d - a(t)^2) / 2t = v1
(2(78m[W]) - 3.0m/s^2[W](6.0s)^2) / 2(6.0s) = v1
(156m[W] - 3.0m/s^2[W](36s)) / 12s = v1
(156m[W] - 108m/s^3[W]) / 12s = v1
This is the problem I'm having. I am not able to subtract the different units of speed. My textbook says that the answer to this question is 4.0m/s[W]. If I were to subtract 108 from 156 and divide by 12, I would get 4.0 correct, but no correct units/direction. Where was my error here? I usually get a little confused when I divide s^2 by s or something similar.