checking answer for a Logarithm question

**JorCherryhead** · February 19th 2010, 05:35 AM

im a little unsure if i have done this right , any chance that someone could look over what i have done.
if F= 50 x 2^3t
find the value of t to 3.s.f.
when F=300

Workings.
300=50x2^3t
6=2^3t
log6=log2^3t
log6=3tlog2
3t=log2/log6
3t=0.387
t=0.129
thankyou

**e^(i*pi)** · February 19th 2010, 05:58 AM

You have your division the wrong way around

$\log(6) = 3t\, \log(2)$

$3t = \frac{\log(6)}{\log(2)}$

$t= \frac{1}{3} \cdot \frac{\log(6)}{\log(2)} = 0.862$

edit: only change the log terms to a decimal for the final answer to avoid rounding errors

edit II: checking using the original equation: $50 \times 2^{3 \cdot 0.862} \approx 300$

**JorCherryhead** · February 19th 2010, 06:23 AM

thankyou=], i have just looked over myself, and have spotted the mistake you pointed out
and i managed to get the right answer
=] cheers

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