These would be clearer if (remaining with ASCII) you write them:Originally Posted byRiley123

R(x) = 5 x^2/(10-x)

Q(x) = -x (8-x)/(3 x^2 + 7 x + 2)

H(x) = (x-7)/(2 x^4 + 7)

where I have to make several guesses at what you actual mean (note

here ^ denotes raising to a power, so x^2 is x squared).

Better yet would be:

The domain of a function is the set on which the function is defined.

From the look of this problem it looks as through we are actually being

asked for the set of real numbers on which the functions are defined.

Though what follows would be equally applicable if we were working

with the complex numbers.

In all of these function definitions both the numerators and

denominators can be evaluated for all real numbers x, but

the functions are undefined when the denominators are zero.

In the first case the denominator is (10-x) which is zero when

x is equal to 10, so the domain of R is the set of all real number

except 10.

The rest are similar, in each case the domain is the set of all

of the reals except the points at which the denominator are

zero (it at all).

RonL