fraction inside brackets

**andyboy179** · February 7th 2010, 05:22 AM

hi i need to simplify this, $fraction inside brackets-untitled5.jpg$ but i don't know how to so can anyone help please?

**Moo** · February 7th 2010, 08:54 AM

Hello,

$\left(\frac 23\right)^{-1}=\frac{2^{-1}}{3^{-1}}=\dfrac{\frac 12}{\frac 13}=\frac 12 \cdot \frac{1}{\frac 13}=\frac 12\cdot 3=\frac 32$

(to show as many steps as possible

**andyboy179** · February 7th 2010, 09:33 AM

Originally Posted by Moo

Hello,

$\left(\frac 23\right)^{-1}=\frac{2^{-1}}{3^{-1}}=\dfrac{\frac 12}{\frac 13}=\frac 12 \cdot \frac{1}{\frac 13}=\frac 12\cdot 3=\frac 32$

(to show as many steps as possible

i know a bit of that but i don't understand how $fraction inside brackets-1.jpg$ , please explain

**BabyMilo** · February 9th 2010, 05:11 AM

Originally Posted by andyboy179

i know a bit of that but i don't understand how $Click image for larger version. Name: 1.jpg Views: 16 Size: 18.1 KB ID: 15293$ , please explain

you should know

$\frac{a}{b} / \frac{c}{d}$

$= \frac{a}{b} * \frac{d}{c}$

$\rightarrow$

$\frac{1}{2} / \frac{1}{3}$

$= \frac{1}{2} * \frac{3}{1}$

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