A particle is moving along a straight line OA with constant acceleration 2ms-2. At OA the particle is moving towards A with speed 5.5ms-1. The distance OA is 20m. Find the time the particle takes to move from O to A.
S=20 V=5.5 A=2 T=?
I used the formula but I got the wrong answer.
Any help?
From what I can gather you've took the initial speed, u as the final speed, v. If we define O as the start point and O to A is the positive direction then at point O the speed given is the initial speed.
My equation is fine, I didn't evaluate both roots in my previous post - the second root is 2.5
(this is one of the suvat equations)
s = 20, u = 5.5, t = t, a = 2
As this is a quadratic rearrange into the form
Solving that using the quadratic formula gives and .