[SOLVED] Physics - Projectile Motion (2d), Vectors

Problem: A projectile is fired in such a way that its horizontal range is equal to 14 times its maximum height. What is the angle of projection?

The work I have done thus far:

Horizontal range $\displaystyle R = 14h$, where $\displaystyle h$ is the maximum height.

The Cartesian coordinates for the maximum height are given by $\displaystyle (R/2, h)$. So, since $\displaystyle R/2 = (14h/2) =7h$, the coordinates are $\displaystyle (7h, h)$.

This gives a right triangle with height $\displaystyle h$ and base $\displaystyle R/2 = 7h$

Thus, $\displaystyle tan(theta) = (h / 7h) = 1/7$

So, $\displaystyle arctan(1/7) = theta = 8.13 degrees$ approximately

This is basically where I'm at. I don't know what to do now or even if I'm heading in the right direction.

P.S. is there a sticky thread or web page that shows a list/tutorial on using the math codes/formatting. The only format I know how to use are the [ math ] tags but they are not always working intuitively for me.

For example, I had to use arctan instead of tan^-1 because the tags did not format ^-1 as in superscript as an exponent would be—I know it's not an exponent in this case, it signifies the "inverse of", but you get my drift. Also, I do not know how to display the "degrees" symbol or Greek letters. Is there a way to do this.

I would list relevant formulas for $\displaystyle R$ and $\displaystyle h$, but I wouldn't know how to format them. Most of them can be found here.

Thanks.