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Math Help - Lamina

  1. #1
    brandon26
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    Lamina

    Can someone please explain to me how to start off this question?

    A uniform semicircular lamina has mass M. A is the midpoint of the diameter and B is on the circumference at the other end of the axis of symetry. A particle of mass m is attached to the lamina at B. The centre of mass of the loaded lamina is at the midpoint of AB. Find in terms of pie, the ration M:m .

    Some one please help quickly
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by brandon26
    Can someone please explain to me how to start off this question?

    A uniform semicircular lamina has mass M. A is the midpoint of the diameter and B is on the circumference at the other end of the axis of symetry. A particle of mass m is attached to the lamina at B. The centre of mass of the loaded lamina is at the midpoint of AB. Find in terms of pie, the ration M:m .

    Some one please help quickly
    Look up the position of the centre of mass C of a semi-circular
    lamina. Assume the lamina's radius is 1 (doesn't matter what it actually
    is as we are after a ratio, but if it worries you call it r). This will
    be on the line AB.

    The centre of mass of your lamina+particle is at the same position
    as the centre of mass of two particles one of mass M at C, and one
    of mass m at B.

    RonL
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