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Math Help - simple clarification

  1. #1
    Senior Member furor celtica's Avatar
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    simple clarification

    ok this is a kinematics thing.
    s(displacement)=93, v(end velocity)=42, t(time)=3/2, find a (acceleration)
    so i used s= vt -0.5at^2 and got a= -80/3
    however the answer is (+ or -) 80/3, and i dont know why. can someone clarify?
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by furor celtica View Post
    ok this is a kinematics thing.
    s(displacement)=93, v(end velocity)=42, t(time)=3/2, find a (acceleration)
    so i used s= vt -0.5at^2 and got a= -80/3
    however the answer is (+ or -) 80/3, and i dont know why. can someone clarify?
    Post the entire question with the original wording (if it was in English).

    It is possible that there is a type in the answers.

    CB
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  3. #3
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    Quote Originally Posted by furor celtica View Post
    ok this is a kinematics thing.
    s(displacement)=93, v(end velocity)=42, t(time)=3/2, find a (acceleration)
    so i used s= vt -0.5at^2 and got a= -80/3
    however the answer is (+ or -) 80/3, and i dont know why. can someone clarify?
    Actually when u get a negetive value like u got here a= -80/3, you keep modulus to the
    number or expression like this"|-80/3|",( the two dashes which are called as modulus) the function of modulus is to neglect any negetive values so that we can write in positve value,

    example:- a = -80/3 when moudulus is placed |a|=|-80/3| which becomes a=80/3,

    so my point is that when modulus is present from starting point of the question, if we remove the modulus from there(question) then the question becomes (+ or -) from there it self,

    watch your question again if there is modulus present in it.
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  4. #4
    Senior Member furor celtica's Avatar
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    captain black there was no text to accompany this exercise, it was a part of a long list of similar mechanics problems
    what do you mean by "It is possible that there is a type in the answers"
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