ok this is a kinematics thing.

s(displacement)=93, v(end velocity)=42, t(time)=3/2, find a (acceleration)

so i used s= vt -0.5at^2 and got a= -80/3

however the answer is (+ or -) 80/3, and i dont know why. can someone clarify?

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- Jan 24th 2010, 11:58 PMfuror celticasimple clarification
ok this is a kinematics thing.

s(displacement)=93, v(end velocity)=42, t(time)=3/2, find a (acceleration)

so i used s= vt -0.5at^2 and got a= -80/3

however the answer is (+ or -) 80/3, and i dont know why. can someone clarify? - Jan 25th 2010, 05:30 AMCaptainBlack
- Jan 25th 2010, 09:12 AMavengerevenge
Actually when u get a negetive value like u got here a= -80/3, you keep modulus to the

number or expression like this"|-80/3|",( the two dashes which are called as modulus) the function of modulus is to neglect any negetive values so that we can write in positve value,

example:- a = -80/3 when moudulus is placed |a|=|-80/3| which becomes a=80/3,

so my point is that when modulus is present from starting point of the question, if we remove the modulus from there(question) then the question becomes (+ or -) from there it self,

watch your question again if there is modulus present in it. - Jan 26th 2010, 10:28 PMfuror celtica
captain black there was no text to accompany this exercise, it was a part of a long list of similar mechanics problems

what do you mean by "It is possible that there is a type in the answers"