Hello furor celtica
Suppose the two are side by side seconds after the start.
Using the graph, the distance travelled is represented by the area under the graph. The area under each graph is the area of a triangle plus the area of a rectangle. For the motor-bike, the length of the rectangle is and for the car it's .
So, equating the two areas, we get:So they're level again after sec.
We can see from the s-t graph that the greatest distance apart will occur when the car's velocity (the gradient of the graph) is equal to the motor-bike's velocity; i.e. m per sec. The car will take sec to accelerate to this speed.
In this time, the motor-bike has covered m; and the car has covered m. So the greatest distance apart m.