Hi, just another question which im slighly unsure about but Ill see if you can help me.
A block of mass 20kg is being pulled along a rough horizonal surface by a rope inclined at an angle of 30degrees to the horizonal.
The coefficient of friction between the block and surface is μ. Model the block as a particle which slides on the surface.
(a) If the tension in the rope is 60 newtons, the block moves at a constant speed.
(i) Show that the magnitude of the normal reaction force acting on the block is 166N
I did so I assume I got this bit correct.
(ii) Find μ
F=μR 51.96=μx166 μ= μ=0.131
(b) If the rope remains at the same angle and the block accelerates at , find the tension in the rope.
I said 'By Newtons 2nd Law Resultant Force = ma
The last question im pretty sure I have no idea what Im talking about, and please excuse the maths talk, werent sure how to get all the symbols in correctly.