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Math Help - Larger the input; the smaller the output

  1. #1
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    Cool Larger the input; the smaller the output

    I wasn't really sure where to post this thread so I thought "Other" was appropriate. Anyways, I am building a spreadsheet and have run into a math problem that I have failed to comprehensively work through.

    Here it is:

    In the spreadsheet I have some resources adding up to a total. We will call this X. It will be the input.
    Secondly, The larger X is the less time it will take.This is the output, we will call this Y.
    So resources =X
    Time =Y
    X(some math goes here)=Y

    Here is some base numbers to work with. If X = 10 thru 12; then Y = 1 sec.
    I know there is most likely some simple high school math involved in here but, I'm a person that need not so much math in life so ya.
    I appreciate any help on this problem if anyone is up to it.

    Thank-You
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  2. #2
    Member integral's Avatar
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    I am not sure what your questions is...

    But I will give it a shot
    If X = 10 -  12; then Y = 1 sec.
    if from 10-12 one second passes, then the change in x per unit of y equals two.
    so
    if x=10 then y must equal \frac{10}{2}=5_s

    If x=1 then y=\frac{x}{2}=.5_s
    so in x=y form it would be
    \frac{x}{2}=y

    If this is your question I hope it helps
    Last edited by integral; December 25th 2009 at 07:12 PM.
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  3. #3
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    It is a good try

    I have to say Thank-you for trying my problem out but unfortunately this solution only halves the resources put into it. What the problem looks for is the more resources put in the less time it takes.

    Example: If there is a manufacturing machine that has variable speeds and the more electricity you give it the faster it goes.
    So, Electricity = resource = X
    Speed = time = Y

    If x=10 to 12 volts; y = 1 sec
    If you add voltage then the time it takes will be less. The less voltage you use the longer it will take. Almost like depreciation... I think that's it. I'll try that out feel free to post on this still.
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  4. #4
    Member integral's Avatar
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    e^-_m = S_m
    and
    S_m=t_l
    were m=more and l=less
    so...
    if e^- is dependent on the amount of resources.

    If r=10 then e^-=12 and if e^-=12 then y=1

    If this is so, I need more to work with than a single equation
    <br />
10r = 12_v=1y

    This could have many solutions. You would need more than one example
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