Can 484/243 be simplified any more? Thanks

I mean the prime common factor is 241 right?

Can someone give me the answer please?

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- November 1st 2005, 03:51 PMNatashaCan 484/243 be simplified any more?
Can 484/243 be simplified any more? Thanks

I mean the prime common factor is 241 right?

Can someone give me the answer please? - November 2nd 2005, 07:16 AMhemza
To simplify 484/243 we try to find all prime factors of both 484 and 243.

important rules :

: if the number is even.__divisible by 2__

: if the sum of all digits is divisible by 3. ex: 321 : the sum is 3+2+4 = 6 so 321 is divisible by 3 (because 6 is divisible by 3).__divisible by 3__

: if the number finishes by 0 or 5.__divisible by 5__

The other factors are by guess and try.

so

484 : it is divisible by 2 so we get 242 and again by 2 so 121 which stops for the 2. Now 1+2+1 is 4 so it is not divisble by 3. So we try 5,7,11,13... until the square root of the number because if there is not number before the square root that devides the NUMBER (the one that we want to factorize) then there will be none after since it takes one before and one after the square root for the product to give the hole number (or both at the middle if the NUMBER is a square). ok, so sqrt of 121 is exactly 11 (which is prime) so 121 = 11*11. We have already all our prime factors, so no need to try the other primes : 484 = 2*2*11*11 (can not get better)

243 : not divisible by 2 but 2+4+3 = 9 is divisible by 3 -> gives 81 and by 3 again and again... actually 243=3*3*3*3*3.

So there is no common factor between 484 and 243. So the fraction 484/243 can not be simplified.