edit: wasn't supposed to post that question

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- Dec 13th 2009, 03:42 PM #1

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- Dec 14th 2009, 03:50 AM #2

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Since you use the word "frustrum" I assume you know that this is the frustrum of a cone. This website: Volume of a Frustum of a Cone

gives the volume as $\displaystyle V= \frac{\pi h}{3}(r^2+ rR+ R^2)$ where "r" and "R" are the radii of the two bases and h is the vertical height of the cone.

Once you have that, you will need to estimate the volume of a single jellybean and divide one volume by the other.

- Dec 14th 2009, 04:33 AM #3

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as HallsofIvy stated:

Once you have that, you will need to estimate the volume of a single jellybean

and divide one volume by the other.

Use that scaled jelly bean to determine the diameter of the top and bottom radius and height of the frustrum & then make your calculations.

You may want to buy a bag of jelly beans, measure a cup full and then count them.

THEN (this is the fun part) mash/smash/pulverise/compress as many jelly beans as possible into the cup.

(YOU NEED TO COUNT THEM BEFORE YOU SQUEEZE'M)

With that you can account for the lost space between the beans, and thus estimate somewhat more acccurately than just a WAG.

.

- Dec 14th 2009, 07:56 AM #4

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Why do the mashing? (I certainly wouldn't want to have to

**eat**that mass of jelly beans!) Just count the number of jelly beans in our cup, then fill the cup with water to determine the number of square inches, perhaps by pouring from the measuring cup into a square pan. That should give you the volume of that many jelly beans including air space.

- Dec 14th 2009, 01:24 PM #5

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