Hi, I've been trying to solve this problem algebraically for a while, but I can't seem to figure it out. How would you solve this step by step? Thanks: x^3 + x = 40
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Not sure if this is what you are looking for but newton's method can find a zero in this function if you choose a good starting guess It is $\displaystyle x_{n+1} = x_n - \frac{f(x_{n})}{f'(x_{n})}$ I would advise making $\displaystyle x_n = 3$
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