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Math Help - Seemingly Easy??

  1. #1
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    Seemingly Easy??

    Hi, I've been trying to solve this problem algebraically for a while, but I can't seem to figure it out. How would you solve this step by step? Thanks:

    x^3 + x = 40
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  2. #2
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    Not sure if this is what you are looking for but newton's method can find a zero in this function if you choose a good starting guess

    It is x_{n+1} = x_n - \frac{f(x_{n})}{f'(x_{n})}

    I would advise making x_n = 3
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