# Seemingly Easy??

• December 10th 2009, 01:17 PM
bandofhorses11
Seemingly Easy??
Hi, I've been trying to solve this problem algebraically for a while, but I can't seem to figure it out. How would you solve this step by step? Thanks:

x^3 + x = 40
• December 10th 2009, 01:30 PM
pickslides
Not sure if this is what you are looking for but newton's method can find a zero in this function if you choose a good starting guess

It is $x_{n+1} = x_n - \frac{f(x_{n})}{f'(x_{n})}$

I would advise making $x_n = 3$