Hi, I've been trying to solve this problem algebraically for a while, but I can't seem to figure it out. How would you solve this step by step? Thanks:

x^3 + x = 40

Printable View

- Dec 10th 2009, 12:17 PMbandofhorses11Seemingly Easy??
Hi, I've been trying to solve this problem algebraically for a while, but I can't seem to figure it out. How would you solve this step by step? Thanks:

x^3 + x = 40 - Dec 10th 2009, 12:30 PMpickslides
Not sure if this is what you are looking for but newton's method can find a zero in this function if you choose a good starting guess

It is $\displaystyle x_{n+1} = x_n - \frac{f(x_{n})}{f'(x_{n})}$

I would advise making $\displaystyle x_n = 3$