the limiting sum of 3 + x + x^2 + ..... is 18. If |x|<1, find x how do you do this??
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Originally Posted by deej813 the limiting sum of 3 + x + x^2 + ..... is 18. If |x|<1, find x how do you do this??
how does that work?? where does the x/1-x come from??
Everything after the 3 is an infinite geometric series. For any infinite geometric series of the form converges to , provided . In your case, the infinite geometric series is . Can you see what and have to be? Can you see what it converges to if ?
wouldn't it be 3/1-x cos isn't a=3??
No. I said the terms AFTER the 3. In other words, your equation is . We are only dealing with the stuff inside the brackets. Edit: It might help if you subtract the 3 to the other side. So the equation becomes .
oh ok i get it thanks
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