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Math Help - general physics #2

  1. #1
    Junior Member
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    general physics #2

    A 400-kg nonuniform beam, 6.0 m long, is loosely pinned at the pivot at P. A 900-kg block is suspended from the end of the boom at A. The boom forms a 30 angle with the horizontal, and is supported by a cable, 4.0 m long, between points D and B. Point B is 4.0 m from P, and point D is 4.0 m above P. The center of mass of the boom is at point C, which is 2.0 m from P. In the figure below, the x-component of the pivot force on the boom is closest to:
    Attached Thumbnails Attached Thumbnails general physics #2-f1q14g1.jpg  
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  2. #2
    Member
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    Sep 2009
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    Well the boom is in equlibrium so you know that the total torque about any point on the boom is equal to zero.

    Therefore I would suggest you pick the point labeled B, because then you have eliminated one unknown (the torque from the cable).
    You know how much torque the block makes, and how much torque from the center of mass of the beam makes.

    So there is just one unknown left, the torque from the pivot.

    Hope that helps.
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