A person is traveling 650 fpm it takes them 25 seconds to stop how many feet did it take?
We don't know the acceleration so let's use an equation that doesn't involve the acceleration:
x = x0 + (1/2)(v0 + v)t
I'm envisioning a coordinate system where + x is in the direction of motion and the origin is at where the person starts to decelerate. Thus x0 = 0 ft, v0 = 650 ft/min, v = 0 ft/min. Using the unit conversion from my first post we get that
v0 = 10.833333 ft/s.
x = (1/2)(v0)t = (1/2)(10.833333 ft/s)(25 s) = 135.417 ft
So 135 ft.