if u want the ratio between A and B it is:
B/A=1-2ln10(B-A)/lnD(B-A)-2Cln10
this was easy . u simply solve the given equation by taking log on both sides.
Hi all,
Firstly first post wasn't sure where to put this apologies if it is wrong, and if this is a totally daft post.
I'm working on a little project for myself and I am having issues with the following:
I have three variables A B C.
A is a lower limit,
B is an upper limit
C is a ratio of the two.
Now I have got this far:
D=10^((C-A)/((B-A)/2))
This gives a % output where if C=A D=1, if B=C D=~100
What I am looking to do is have an output that is a ratio of A to B:
For example:
If A=C Ratio=0
If A=B Ratio= ∞
Hopefully that will make some sense?
Sorry perhaps I should have been clearer, although what you said may still apply.
Ill try with another example.
As I said A and B are are the upper and lower limits, they can change but C which is physically measured will always land between them.
I need to find D which is the ratio of A to B. D will always land within 10:1 to 100:1 of A:B.