For the acceleration i got 0.713 m/s^2 also.
((980-750) + (mgsin(3)) = 819.826 then divide by 1150
Can some one help me with 5 ii) a)?
Here is what i've done.
Trailer:
fx = P-250gsin3-150=250a
fy = R-250gcos3=0
Car:
fx = 980-900gsin3-600-P=900a
fy = R-900gsin3=0
so therefore
980-900gsin3-600=P+900a
-250gsin3-150=250a-P
right? simultaneous equation then solve for P and a.
which comes out as:
a=-0.313 ms^-2 (3s.f.)
P=200N
but the answer from the mark scheme says P= 200N but a = 0.713ms^-2 which suggests the equation should be
980+900gsin3-600=P+900a
+250gsin3-150=250a-P
can someone explain what i've done wrong and which one is right.
Sorry for being quite long. THanks for your help.