Rearranging Equation (Heat Transfer)

**jimmychoo** · November 28th 2009, 12:31 AM

Can someone please show me step by step how to rearrange this equation to get T2?

K*((T1-T2)/L)=h(T2-T0)

Much appreciated!

**mathaddict** · November 28th 2009, 12:42 AM

Originally Posted by jimmychoo

Can someone please show me step by step how to rearrange this equation to get T2?

K*((T1-T2)/L)=h(T2-T0)

Much appreciated!

HI

$k \left(\frac{T_1-T_2}{L}\right) =h(T_2-T_0)$

$\frac{kT_1-kT_2}{L}=T_2h-T_0h$

$kT_1+LT_0h=LT_2h+kT_2$

Bring out $T_2$

so $T_2=\frac{kT_1+LT_0h}{Lh+k}$

**jimmychoo** · November 28th 2009, 01:02 AM

Many thanks. I suppose when you think about it it is pretty logical. One more question though. How do you go about bringing out T2? i.e. why does 'Lh+k' become the denominator?