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Thread: Rearranging Equation (Heat Transfer)

  1. #1
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    Rearranging Equation (Heat Transfer)

    Can someone please show me step by step how to rearrange this equation to get T2?

    K*((T1-T2)/L)=h(T2-T0)

    Much appreciated!
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  2. #2
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    Quote Originally Posted by jimmychoo View Post
    Can someone please show me step by step how to rearrange this equation to get T2?

    K*((T1-T2)/L)=h(T2-T0)

    Much appreciated!
    HI

    k \left(\frac{T_1-T_2}{L}\right) =h(T_2-T_0)

    \frac{kT_1-kT_2}{L}=T_2h-T_0h

    kT_1+LT_0h=LT_2h+kT_2

    Bring out T_2

    so T_2=\frac{kT_1+LT_0h}{Lh+k}
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  3. #3
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    Many thanks. I suppose when you think about it it is pretty logical. One more question though. How do you go about bringing out T2? i.e. why does 'Lh+k' become the denominator?
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  4. #4
    Senior Member Stroodle's Avatar
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    LT_2h+kT_2 can be factorised to T_2(Lh+k)

    so if you divide both sides by Lh+k the T_2 will be left on it's own
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  5. #5
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    Where have my maths basics gone. Thanks guys.
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