# Thread: Rearranging Equation (Heat Transfer)

1. ## Rearranging Equation (Heat Transfer)

Can someone please show me step by step how to rearrange this equation to get T2?

K*((T1-T2)/L)=h(T2-T0)

Much appreciated!

2. Originally Posted by jimmychoo
Can someone please show me step by step how to rearrange this equation to get T2?

K*((T1-T2)/L)=h(T2-T0)

Much appreciated!
HI

$\displaystyle k \left(\frac{T_1-T_2}{L}\right) =h(T_2-T_0)$

$\displaystyle \frac{kT_1-kT_2}{L}=T_2h-T_0h$

$\displaystyle kT_1+LT_0h=LT_2h+kT_2$

Bring out $\displaystyle T_2$

so $\displaystyle T_2=\frac{kT_1+LT_0h}{Lh+k}$

3. Many thanks. I suppose when you think about it it is pretty logical. One more question though. How do you go about bringing out T2? i.e. why does 'Lh+k' become the denominator?

4. $\displaystyle LT_2h+kT_2$ can be factorised to $\displaystyle T_2(Lh+k)$

so if you divide both sides by $\displaystyle Lh+k$ the $\displaystyle T_2$ will be left on it's own

5. Where have my maths basics gone. Thanks guys.