Hi, can someone please help me with this problem. Thanks!
Suppose that 1.01 g of rubbing alcohol (C3H8O) evaporates from a 55.0 g aluminium block. If the aluminum block is initially at 25 degrees cel., what is the final temp. of the block after the evaporation of the alcohol? Assume the heat required for the vaporization of alcohol comes from the alum. block and that the alcohol vaporizes at 25 degrees cel.
What I did but got incorrect answer:
1.01 g x 664 J/g = 670.64 J
55g x 0.9J/g = 49.5J
670.64J/49.5J = 13.5
25-13.5 = 11.5 but this is not the correct answer. Can you tell me what I did wrong. Thanks again.