1. ## adding and dividing fractions

this is my question:

(3 $\frac{1}{7}$ + $\frac{1}{4}$) divided $\frac{3}{4}$

how would i work this question out???

2. Originally Posted by andyboy179
this is my question:

(3 $\frac{1}{7}$ + $\frac{1}{4}$) divided $\frac{3}{4}$

how would i work this question out???
First, you should combine the fractions in the parenthesis. To do this, find a common denominator:

$3\frac{1}{7} = \frac{22}{7} = \frac{88}{28}$
$\frac{1}{4} = \frac {7}{28}$

Now we can add the two fractions:

$\frac{88}{28} + \frac{7}{28} = \frac{95}{28}$

Now divide:

$\frac{95}{28} \div \frac{3}{4}$

Dividing like that makes the problem harder, so we'll multiply $\frac{109}{28}$ by the reciprocal of $\frac{3}{4}$, which means we do this:

$\frac{95}{28} \times \frac{4}{3} = \frac {95}{21}$

3. This probably goes in the other section but do you mean this:

$\frac{3\frac{1}{7}+\frac{1}{4}}{\frac{3}{4}}$?

4. Originally Posted by Cursed
First, you should combine the fractions in the parenthesis. To do this, find a common denominator:

$3\frac{1}{7} = \frac{22}{7} = \frac{88}{28}$
$\frac{1}{4} = \frac {7}{28}$

Now we can add the two fractions:

$\frac{88}{28} + \frac{7}{28} = \frac{95}{28}$

Now divide:

$\frac{95}{28} \div \frac{3}{4}$

Dividing like that makes the problem harder, so we'll multiply $\frac{109}{28}$ by the reciprocal of $\frac{3}{4}$, which means we do this:

$\frac{95}{28} \times \frac{4}{3} = \frac {95}{21}$