this is my question:

(3 $\displaystyle \frac{1}{7}$ + $\displaystyle \frac{1}{4}$) divided $\displaystyle \frac{3}{4}$

how would i work this question out???

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- Nov 22nd 2009, 11:06 AMandyboy179adding and dividing fractions
this is my question:

(3 $\displaystyle \frac{1}{7}$ + $\displaystyle \frac{1}{4}$) divided $\displaystyle \frac{3}{4}$

how would i work this question out??? - Nov 22nd 2009, 12:15 PMCursed
First, you should combine the fractions in the parenthesis. To do this, find a common denominator:

$\displaystyle 3\frac{1}{7} = \frac{22}{7} = \frac{88}{28}$

$\displaystyle \frac{1}{4} = \frac {7}{28}$

Now we can add the two fractions:

$\displaystyle \frac{88}{28} + \frac{7}{28} = \frac{95}{28}$

Now divide:

$\displaystyle \frac{95}{28} \div \frac{3}{4}$

Dividing like that makes the problem harder, so we'll multiply $\displaystyle \frac{109}{28}$ by the reciprocal of $\displaystyle \frac{3}{4}$, which means we do this:

$\displaystyle \frac{95}{28} \times \frac{4}{3} = \frac {95}{21}$ - Nov 22nd 2009, 12:17 PMANDS!
This probably goes in the other section but do you mean this:

$\displaystyle \frac{3\frac{1}{7}+\frac{1}{4}}{\frac{3}{4}}$? - Nov 23rd 2009, 07:01 AMandyboy179