indices (i think)

**andyboy179** · November 22nd 2009, 10:08 AM

hi this is my question:

5^6 x 25^2

would it = 5^8?

**Amer** · November 22nd 2009, 10:19 AM

Originally Posted by andyboy179

hi this is my question:

5^6 x 25^2

would it = 5^8?

$5^6 \times 25^2 =5^6\times (5^2)^2= 5^6 \times 5^{2\cdot 2} = 5^6 \times 5^4 = 5^{6+4} = 5^{10}$

**andyboy179** · November 22nd 2009, 10:22 AM

Originally Posted by Amer

$5^6 \times 25^2 =5^6\times (5^2)^2= 5^6 \times 5^{2\cdot 2} = 5^6 \times 5^4 = 5^{6+4} = 5^{10}$

how did u get (5^2)^2?

**e^(i*pi)** · November 22nd 2009, 10:24 AM

Originally Posted by andyboy179

how did u get (5^2)^2?

Because $5^2 = 25$

**Amer** · November 22nd 2009, 10:25 AM

Originally Posted by andyboy179

how did u get (5^2)^2?

$25 = 5\times 5 =5^2$

$25^2 = 25 \times 25 = 5^2 \times 5^2 = 5^{2+2} = 5^4$

**andyboy179** · November 22nd 2009, 10:26 AM

oh i understand now, thanks alot

Thread: indices (i think)