Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors
4x+8 4(x+2) x+2
-------- ----------- ------- = 1 ?
3x+6 3(x+2) x+2
is this correct 1(or leave it to x+2/x+2)
Hello, wolfhound!
Your typing is confusing and your answer is dreadfully wrong.
I'll guess what you're trying to say.
Factor the numerator and denominator and cancel out any common factors.
. . $\displaystyle \frac{4x+8}{3x+6}$
. . $\displaystyle \frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$