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Math Help - Factorisation

  1. #1
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    Factorisation

    Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors
    4x+8 4(x+2) x+2
    -------- ----------- ------- = 1 ?
    3x+6 3(x+2) x+2

    is this correct 1(or leave it to x+2/x+2)
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  2. #2
    Super Member bigwave's Avatar
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    the (x+2) cancel out

     <br />
\frac{4x + 8}{3x + 6}<br />

     <br />
= \frac{4(x+2)}{3(x+2)}<br />

    cancel out (x+2)

     <br />
= \frac{4}{3}<br />
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  3. #3
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    Hello, wolfhound!

    Your typing is confusing and your answer is dreadfully wrong.
    I'll guess what you're trying to say.


    Factor the numerator and denominator and cancel out any common factors.

    . . \frac{4x+8}{3x+6}

    . . \frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}

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  4. #4
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    Quote Originally Posted by Soroban View Post
    Hello, wolfhound!

    Your typing is confusing and your answer is dreadfully wrong.
    I'll guess what you're trying to say.



    . . \frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}

    sorry yes thank you.
    I must download Latex
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  5. #5
    Super Member bigwave's Avatar
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    so that's how you do cancel out in latex
    now I know......
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