Factorisation

**wolfhound** · November 20th 2009, 08:50 AM

Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors
4x+8 4(x+2) x+2
-------- ----------- ------- = 1 ?
3x+6 3(x+2) x+2

is this correct 1(or leave it to x+2/x+2)

**bigwave** · November 20th 2009, 09:07 AM

$ \frac{4x + 8}{3x + 6} $

$ = \frac{4(x+2)}{3(x+2)} $

cancel out $(x+2)$

$ = \frac{4}{3} $

**Soroban** · November 20th 2009, 09:09 AM

Hello, wolfhound!

Your typing is confusing and your answer is dreadfully wrong.
I'll guess what you're trying to say.

Factor the numerator and denominator and cancel out any common factors.

. . $\frac{4x+8}{3x+6}$

. . $\frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$

**wolfhound** · November 20th 2009, 09:11 AM

Originally Posted by Soroban

Hello, wolfhound!

Your typing is confusing and your answer is dreadfully wrong.
I'll guess what you're trying to say.

. . $\frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$

sorry yes thank you.
I must download Latex

**bigwave** · November 20th 2009, 09:25 AM

so that's how you do cancel out in latex
now I know......

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