Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors

4x+8 4(x+2) x+2

-------- ----------- ------- = 1 ?

3x+6 3(x+2) x+2

is this correct 1(or leave it to x+2/x+2)

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- Nov 20th 2009, 08:50 AMwolfhoundFactorisation
Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors

4x+8 4(x+2) x+2

-------- ----------- ------- = 1 ?

3x+6 3(x+2) x+2

is this correct 1(or leave it to x+2/x+2) - Nov 20th 2009, 09:07 AMbigwavethe (x+2) cancel out
$\displaystyle

\frac{4x + 8}{3x + 6}

$

$\displaystyle

= \frac{4(x+2)}{3(x+2)}

$

cancel out $\displaystyle (x+2)$

$\displaystyle

= \frac{4}{3}

$ - Nov 20th 2009, 09:09 AMSoroban
Hello, wolfhound!

Your typing is confusing and your answer is dreadfully wrong.

I'llwhat you're trying to say.__guess__

Quote:

Factor the numerator and denominator and cancel out any common factors.

. . $\displaystyle \frac{4x+8}{3x+6}$

. . $\displaystyle \frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$

- Nov 20th 2009, 09:11 AMwolfhound
- Nov 20th 2009, 09:25 AMbigwave
so that's how you do cancel out in latex

now I know......