Factorisation

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November 20th 2009, 08:50 AM
wolfhound

Factorisation

Q: Factorise the numerator and denominator of each of the following and then cancel out any common factors
4x+8 4(x+2) x+2
-------- ----------- ------- = 1 ?
3x+6 3(x+2) x+2

is this correct 1(or leave it to x+2/x+2)
November 20th 2009, 09:07 AM
bigwave

the (x+2) cancel out

$ \frac{4x + 8}{3x + 6} $

$ = \frac{4(x+2)}{3(x+2)} $

cancel out $(x+2)$

$ = \frac{4}{3} $
November 20th 2009, 09:09 AM
Soroban

Hello, wolfhound!

Your typing is confusing and your answer is dreadfully wrong.
I'll guess what you're trying to say.

Quote:

Factor the numerator and denominator and cancel out any common factors.

. . $\frac{4x+8}{3x+6}$

. . $\frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$
November 20th 2009, 09:11 AM
wolfhound

Quote:

Originally Posted by Soroban

Hello, wolfhound!

Your typing is confusing and your answer is dreadfully wrong.
I'll guess what you're trying to say.

. . $\frac{4x + 8}{3x+6} \;\;=\;\;\frac{4\,(x+2)}{3\,(x+2)} \;\;=\;\;\frac{4\,{\color{red}\rlap{//////}}(x+2)}{3\,{\color{red}\rlap{//////}}(x+2)} \;\;=\;\; \frac{4}{3}$

sorry yes thank you.
I must download Latex
November 20th 2009, 09:25 AM
bigwave

so that's how you do cancel out in latex
now I know......

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