1. ## very hard question

hi this is my question:

(2 x 3^7) x ( 3 x 2^5) = 2^n x 3^m find n and m

i am VERY confused on what to do, can anyone help please?!?

2. put it this way:
(2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m
can you do it now?

3. Originally Posted by BabyMilo
put it this way:
(2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m
can you do it now?

how did u get those numbers? some have changed

read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right?
then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7

you can add the brackets in if you want then.

5. sorry i understand now, i was being dumb. is that all i would write?

6. Originally Posted by BabyMilo

read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right?
then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7

you can add the brackets in if you want then.

what would the answer be? or would i just put (2 x 2^5) x ( 3 x 3^7)

7. 2 x 2^5 = 2^6
3 x 3^7 = 3^8
so n=6
and m=8

think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3)

8. Originally Posted by BabyMilo
2 x 2^5 = 2^6
3 x 3^7 = 3^8
so n=6
and m=8

think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3)

i understand now, thats alot