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Math Help - very hard question

  1. #1
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    very hard question

    hi this is my question:

    (2 x 3^7) x ( 3 x 2^5) = 2^n x 3^m find n and m


    i am VERY confused on what to do, can anyone help please?!?
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  2. #2
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    put it this way:
    (2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m
    can you do it now?
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  3. #3
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    Quote Originally Posted by BabyMilo View Post
    put it this way:
    (2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m
    can you do it now?

    how did u get those numbers? some have changed
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  4. #4
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    your bracket is misleading that all.

    read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right?
    then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7

    you can add the brackets in if you want then.
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  5. #5
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    sorry i understand now, i was being dumb. is that all i would write?
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  6. #6
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    Quote Originally Posted by BabyMilo View Post
    your bracket is misleading that all.

    read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right?
    then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7

    you can add the brackets in if you want then.

    what would the answer be? or would i just put (2 x 2^5) x ( 3 x 3^7)
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  7. #7
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    2 x 2^5 = 2^6
    3 x 3^7 = 3^8
    so n=6
    and m=8

    think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3)
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  8. #8
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    Quote Originally Posted by BabyMilo View Post
    2 x 2^5 = 2^6
    3 x 3^7 = 3^8
    so n=6
    and m=8

    think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3)

    i understand now, thats alot
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