hi this is my question: (2 x 3^7) x ( 3 x 2^5) = 2^n x 3^m find n and m i am VERY confused on what to do, can anyone help please?!?
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put it this way: (2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m can you do it now?
Originally Posted by BabyMilo put it this way: (2 x 2^5) x ( 3 x 3^7) = 2^n x 3^m can you do it now? how did u get those numbers? some have changed
your bracket is misleading that all. read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right? then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7 you can add the brackets in if you want then.
sorry i understand now, i was being dumb. is that all i would write?
Originally Posted by BabyMilo your bracket is misleading that all. read it like this (2 x 3^7) x ( 3 x 2^5) = 2 x 3^7 x 3 x 2^5 right? then rearrange a bit 2 x 3^7 x 3 x 2^5 = 2 x 2^5 x 3 x 3^7 you can add the brackets in if you want then. what would the answer be? or would i just put (2 x 2^5) x ( 3 x 3^7)
2 x 2^5 = 2^6 3 x 3^7 = 3^8 so n=6 and m=8 think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3)
Originally Posted by BabyMilo 2 x 2^5 = 2^6 3 x 3^7 = 3^8 so n=6 and m=8 think of it as 2 x (2x2x2x2x2) and 3 x (3x3x3x3x3x3x3) i understand now, thats alot
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