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Math Help - Conservation of Energy

  1. #1
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    Conservation of Energy

    There is a 3Kg crate at the bottom of an incline, initially moving at 3 m.s^{-1}. The incline is 20 degrees and frictionless. The crate moves through a displacement of d metres and comes to a stop. Calculate d.

    I did the following:

    (E_{p} + E_{k})_{Bottom} = (E_{p} + E_{k})_{Top}
     0 + {1/2}.(3).(3)^2 = (3).(9.8).Sin20.d + 0
     d = 1.34m

    Is this correct?
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  2. #2
    MHF Contributor
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    Quote Originally Posted by MarcoMP View Post
    There is a 3Kg crate at the bottom of an incline, initially moving at 3 m.s^{-1}. The incline is 20 degrees and frictionless. The crate moves through a displacement of d metres and comes to a stop. Calculate d.

    I did the following:

    (E_{p} + E_{k})_{Bottom} = (E_{p} + E_{k})_{Top}
     0 + {1/2}.(3).(3)^2 = (3).(9.8).Sin20.d + 0
     d = 1.34m

    Is this correct?
    HI

    From the principle of conservation of energy , PE gained = KE lost

    \frac{1}{2}mu^2=\frac{1}{2}mv^2+mgh

    \frac{1}{2}(3)(3)^2=0+(3)(9.81)(d\sin 20)

    d=1.341

    I agree with your answer .
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  3. #3
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    Smile

    looks fine to me.
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