Every year at Coopers Hill in Gloucestershire (UK) there is a cheese rolling festival where people race down the hill after a rolling disc of Gloucestershire cheese, the winner getting to keep the cheese. (No, I'm not kidding look

here. It seems there will even be an event in Whistler, BC next year if you are really interested.)

Given that the

moment of inertia of a disc of

mass m and radius r about its axis of symmetry is

, what is the

speed of the cheese's centre of

mass after it has descended a vertical distance of 17.0 m from the top of the hill? Assume that the cheese rolls without slipping.

[

Acceleration due to gravity, g=9.81 ms-2]

[Specify your answer in units of 'm/s' (without quotes)]