at max displacement,
the particle oscillates between and
because of symmetry, equilibrium will midway between these two x-values, at .
at equilibrium, the particle is at
hz
Yet another unsolved homework problem, this one involving simple harmonic motion:
"The speed of a point moving along the x-axis is given by
v^2 = 108 + 72x - 36x^2
Find the mean position, the amplitude and the frequency of the motion."
What do they mean find the mean position? Shouldn't it be at the centre? I know that I can use the formula
x = Acos(ωt + α)
to find amplitude (A), and
f = 1/T where T = 2π/ω
to find frequency (f)
But I can't even seem to get started. Thanks for any help