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  1. #1
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    Chemistry

    • A 50.0 ml sample of Ca(OH)2 is titrated with 36.0 ml of 0.05 M HCl solution to an endpoint. What is the molarity of the Ca(OH)2 solution?
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  2. #2
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    Quote Originally Posted by daphnewoon View Post
    • A 50.0 ml sample of Ca(OH)2 is titrated with 36.0 ml of 0.05 M HCl solution to an endpoint. What is the molarity of the Ca(OH)2 solution?
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  3. #3
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    Equation = Ca(OH)2 + 2HCl -> CaCl2 + 2H20

    36.0 ml*(0.05M/1ml) = 1.8 mmol HCl

    since it requires 2moles of HCl to react with 1 mole of Ca(OH)2

    1.8/2= 0.9mmol is need

    0.9mmol/50ml of Ca(OH)2 = 0.018mol

    Here is your answer: 0.018mol

    If you still dont understand you can go on Chemistry - Google Ϯ to page 384 of the book.

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