Edit: Nevermind. I figured out that I was using the wrong coords and the wrong mass of the second object. The correct answer was -.25m.

The formula for center of mass is $\displaystyle r_x=\frac{x_1*m_1+x_2*m_2+x_3*m_3}{m_1+m_2+m_3}$A uniform square plate 6.mon a side has had a square piece 2.mon a side cut out of it (see the figure). The center of that piece is at x=2m, y = 0. The center of the square plate is at x = y = 0. Find the coordinates of the center of mass of the remaining piece. x-component (m)?

$\displaystyle m=(density)Ah$ Where A is area and h is height of the object.

This is a very easy topic and a very easy question. I'm just having trouble seeing where the coords are. In my attempt I had the following values:

$\displaystyle x_1=x_2=4$

$\displaystyle x_3=1$

$\displaystyle m_1=m_2=2^2*1*1=4$

$\displaystyle m_3=6^2*1*1=36$

My final answer was 1.54m. The online system tells me this is wrong. Does anyone see where I went wrong?

Thanks.